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### Moles in -nFEcell

Posted: Mon Feb 25, 2019 2:03 pm
How do we know what n is? Is it just the sum of the coefficients of the products?

### Re: Moles in -nFEcell

Posted: Mon Feb 25, 2019 2:05 pm
n represents the number of electrons transferred in a balanced redox reaction

### Re: Moles in -nFEcell

Posted: Mon Feb 25, 2019 2:10 pm
To find n, you must write out both of the half reactions and balance the equations. Once the number of electrons on both sides of the reaction are consistent, this is how many moles should be used in this equation.

### Re: Moles in -nFEcell

Posted: Mon Feb 25, 2019 2:12 pm
n is the number of moles (stoichiometric coefficent) for the electrons transferred in the balanced redox reaction

### Re: Moles in -nFEcell

Posted: Mon Feb 25, 2019 2:54 pm
To be clear n is the number of moles of electrons in the balanced redox reaction, not the number of electrons.

### Re: Moles in -nFEcell

Posted: Tue Feb 26, 2019 12:21 pm
As everyone stated before n represents the moles of electrons. To figure it out you could do the reduction and oxidation half-reactions for the reaction to calculate it. Balance the reactions so there are equal number of electrons for both the oxidation and reduction half reactions. I just want to note that even if you change the coefficients of the half reactions the E° For the reactions does not change because it is a INTENSIVE property!