8 posts • Page 1 of 1
n represents how many electrons are being transferred in the reaction. The value should be the same whether you are looking at the oxidation or reduction half reactions as the number of electrons should be the same if the half reactions are balanced.
It is important to keep in mind that n as the number of electrons only applies to the equation deltaG = -nFE, deltaG° = -nFE°, or Wmax = -nFE (these are the only equations from class). When using n in other equation such as the ideal gas law (PV = nRT), n is the number of moles.
In order to find n (the number of electrons transferred) write down both half reactions and balance them. You always want to make sure that the number of electrons being transferred is the same amount for both half reactions.
Once the redox reaction is balanced you should have an equal number of electrons on both sides of the equation. That will be the n value. There can only be one value for n. If you think you have two then you did not balance your redox equations correctly.
After you create your two half reactions, you need to balance the amount of electrons in order to combine the reaction into one. In the process of balancing out the amount of electrons, you find your number of moles of electrons. It is the number of e- you used to balance the reaction.
Angela Cong 3C wrote:Sometimes there are cases where you simplify the balanced redox reaction, would n be the number of moles before simplification or would it be the number of moles after simplification?
In a redox reaction, you would look at the half-reactions you used to cancel out the electrons before you formed the balanced redox reaction. The cancelled out electrons are the number of electrons transferred, and so that would be the value n!
Who is online
Users browsing this forum: No registered users and 1 guest