CHEMISTRY COMMUNITY

In the equation deltaG=-nFE^0, what is n?

In lecture he said that n is based on the number of moles of electrons gained/lost in the redox reaction.

If they just give you a balanced redox reaction, do you then just look back at the half reactions and balance the charges again to figure out what the difference in moles of electrons were to get your n?

Follow up question: is n supposed to be (moles of electrons in reactants)-(moles of electrons in products) or is it (moles of electrons in products)-(moles of electrons in reactants)?

What Subhani said above is correct. I would just write the balanced half reactions and combine them to see what the number of electrons that cancel out each other is. That is your n. Hope that helps!

n in this equation is the moles of electrons transferred in your balanced redox reaction

"n" is the number of electrons transferred in a balanced redox reaction. For example, in the reduction of Ce4+ to Ce3+ with I-, there are 2 electrons being transferred, so n = 2.

n is the number of electrons transferred, to find it you would find the two half reactions, and balance them out for an equal #e. for example if cathode reaction has 2e transfer and anode reaction has 3e transfer, you would balance them for both of them to have a 6e transfer, in which case your n would be 6.

n is the number of electrons involved in the equation. For example, if given a balanced redox reaction, you would have to reseperate the half reactions to find the number of electrons that are being cancelled out.