## 14.9 ch 14

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

Jennifer Torres 2L
Posts: 62
Joined: Tue Nov 14, 2017 3:01 am

### 14.9 ch 14

Hello! I was wondering if someone could explain how to get started/ work through on this problem a bit confused?

Athena L 1B
Posts: 59
Joined: Fri Sep 28, 2018 12:18 am

### Re: 14.9 ch 14

Can you post the question?

404975170
Posts: 68
Joined: Thu Jul 27, 2017 3:00 am

### Re: 14.9 ch 14

The Question is:
A student was given a standard Cu(s)| Cu^2+ (aq) half-cell and another half-cell containing an unknown metal M immersed in 1.00 M M(NO3)2 (aq). When the copper was connected as the anode at 25C, the cell potential was found to be -0.689 V. What is the reduction potential for the unknown M2+/M couple?

I know I need to solve for the E for copper and then plug into E=E(cathode)-E(anode) but I’m not sure which equation to use?

404975170
Posts: 68
Joined: Thu Jul 27, 2017 3:00 am

### Re: 14.9 ch 14

Okay so I just realized the cell potential for Cu is given so then you just plug in:
-0.689 V=E(cathode)-(0.34V)
to get the reduction potential of the anode