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### Finding n

Posted: Thu Feb 28, 2019 3:01 pm
Is n just the number of electrons that appear on either side of each half reaction (ie: amount of electrons added to the oxidation side, that are then transferred from anode to cathode?)

### Re: Finding n

Posted: Thu Feb 28, 2019 3:06 pm
Yes. For $\Delta G=-nFE$, n is the number of electrons that are transferred in the reaction

### Re: Finding n

Posted: Thu Feb 28, 2019 4:17 pm
n is the number of electrons being transferred. However, make sure that both half-reactions are balanced before using n, as the number of electrons being transferred should stay consistent in the equation.

### Re: Finding n

Posted: Fri Mar 01, 2019 2:32 pm
When finding n, you would want to solve for both the oxidation and the reduction half reactions. Once you get there, see how many moles of electrons are transferred in the completely balanced redox reaction; this number of moles is the number you want to use for n.

### Re: Finding n

Posted: Fri Mar 01, 2019 4:04 pm
Yes initially I believed it had to do with stoichiometric coefficients since it had to do with moles but it has to do with the oxiditation state and electrons transferred in a balanced redox equation.

### Re: Finding n

Posted: Fri Mar 01, 2019 4:57 pm
Yes, n is the number of moles of electrons transferred and can be found through the oxidation or reduction half reactions.

### Re: Finding n

Posted: Sun Mar 03, 2019 10:08 pm
So it is the -e- that is in your reaction.

### Re: Finding n

Posted: Sun Mar 03, 2019 11:22 pm
Yeah a lot of people get it mixed up with the total moles of reactants and products but it is the electrons transferred. Always make sure it is the number of electrons after you balance the half-reactions and make sure the electrons cancel out.

### Re: Finding n

Posted: Mon Mar 04, 2019 12:34 am
Yes, it is the amount of electrons added on both sides (of course they should be the same number).

### Re: Finding n

Posted: Mon Mar 04, 2019 12:55 am
For example, if one mole of Fe were being oxidized to Fe2+, n would be 2 because 2 moles of electrons would be transferred. If Fe had a coefficient other than one, you would multiply it by 2.

### Re: Finding n

Posted: Mon Mar 04, 2019 9:42 am
n is the number of electrons transferred after you've balance the oxidation and half reactions.

### Re: Finding n

Posted: Mon Mar 11, 2019 8:38 pm
n is just the number of balanced electrons

### Re: Finding n

Posted: Tue Mar 12, 2019 3:17 pm
So if one half reaction transfers 2 electrons and the other half reaction transfers 3 electrons, would n be 6? This way they would cancel out in the total reaction.