## Test 2

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

Maggie Doan 1I
Posts: 61
Joined: Fri Sep 28, 2018 12:24 am

### Test 2

7b. The combustion of a gas used to heat a BBQ at a pool party.

Would this be a spontaneous reaction?

AnnaYan_1l
Posts: 96
Joined: Fri Apr 06, 2018 11:05 am
Been upvoted: 1 time

### Re: Test 2

I have the exact same question! When I was doing the test, I assumed that the gibbs free energy would be greater than 0. However, is it less than 0 (spontaneous) because combustion involves purely adding oxygen and doesn't require heat? (and, would it be correct to say that the BBQ being made from the heat would be non spontaneous)? Is this all correct?

Ryan Danis 1J
Posts: 66
Joined: Fri Sep 28, 2018 12:18 am

### Re: Test 2

I believe it would be spontaneous because combustion is an exothermic process, so delta H would be negative. Because delta G = delta H - T delta S, and delta H is negative, delta G should be negative. When delta G is negative, the reaction is spontaneous.

Maggie Doan 1I
Posts: 61
Joined: Fri Sep 28, 2018 12:24 am

When would ΔG=0?