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I have the exact same question! When I was doing the test, I assumed that the gibbs free energy would be greater than 0. However, is it less than 0 (spontaneous) because combustion involves purely adding oxygen and doesn't require heat? (and, would it be correct to say that the BBQ being made from the heat would be non spontaneous)? Is this all correct?
I believe it would be spontaneous because combustion is an exothermic process, so delta H would be negative. Because delta G = delta H - T delta S, and delta H is negative, delta G should be negative. When delta G is negative, the reaction is spontaneous.
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