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G(not) and G

Posted: Sun Feb 23, 2020 10:16 pm
by Johnathan Smith 1D
What is the difference between G(not) and G?

Re: G(not) and G

Posted: Sun Feb 23, 2020 10:20 pm
by Tracy Tolentino_2E
G(not) is the standard Gibbs Free energy. So it's the energy in standard conditions. (1 M, 1atm, 25 degrees Celsius)
G is Gibbs Free energy in other conditions

Re: G(not) and G

Posted: Sun Feb 23, 2020 10:58 pm
by ASetlur_1G
Is it correct to say that G(not) is used at equilibrium (K value) and G is used for other conditions (Q value)?

Re: G(not) and G

Posted: Sun Feb 23, 2020 11:03 pm
by KarineKim2L
In addition to all of the above, the relationship between G not and G can be seen in the equation G not= G+RTlnQ.

Re: G(not) and G

Posted: Sun Feb 23, 2020 11:14 pm
by Rafsan Rana 1A
Isn't the equation G = Gnot + RTlnQ ?

Re: G(not) and G

Posted: Sun Feb 23, 2020 11:16 pm
by Jainam Shah 4I
G(not) is at standard conditions whereas G itself doesn't have to be at standard conditions.

Re: G(not) and G

Posted: Sun Feb 23, 2020 11:37 pm
by Sean Tran 2K
G(not) represents standard Gibbs Free energy.

Re: G(not) and G

Posted: Mon Feb 24, 2020 12:37 am
by Leyna Dang 2H
G(not) is at standard Gibbs free energy, thus it is under standard conditions, unlike G.

Re: G(not) and G

Posted: Mon Feb 24, 2020 1:04 am
by Sanjana K - 2F
Rafsan Rana 1A wrote:Isn't the equation G = Gnot + RTlnQ ?


Yes, it should be delta G = delta G(naught) + RTlnQ.

Re: G(not) and G

Posted: Tue Feb 25, 2020 7:15 pm
by Maya Beal Dis 1D
In problem 5G.13 you calculate the delta G of the reaction at equilibrium and then use whether that value is positive or negative to see which way the reaction will proceed (towards reactants or products), but if the reaction is at equilibrium doesn't that mean the reaction is going both ways at the exact same rate and would therefore favor neither direction?

Re: G(not) and G

Posted: Tue Feb 25, 2020 7:17 pm
by KaleenaJezycki_1I
ASetlur_1G wrote:Is it correct to say that G(not) is used at equilibrium (K value) and G is used for other conditions (Q value)?


Yes for the most part.

Re: G(not) and G

Posted: Tue Feb 25, 2020 9:47 pm
by BCaballero_4F
ASetlur_1G wrote:Is it correct to say that G(not) is used at equilibrium (K value) and G is used for other conditions (Q value)?

Yes this is essentially correct to say

Re: G(not) and G

Posted: Tue Feb 25, 2020 9:48 pm
by 205405339
G9not) is under standard conditions whereas G is not and G(n0t) will contribute to the value of G

Re: G(not) and G

Posted: Wed Feb 26, 2020 12:24 pm
by Nathan Rothschild_2D
Naught always means 1M of solution or 1 atm at 298K (same as 25 Celsius)

Re: G(not) and G

Posted: Wed Feb 26, 2020 1:25 pm
by Zoe Gleason 4F
Gnaught will be under standard conditions, which are 1.0M, 1atm, and 25C.

Re: G(not) and G

Posted: Sun Mar 08, 2020 10:51 pm
by Cindy Adiwidjaja 1B
Whenever there is a ⁰ on anything (G, H, S), it means that that process is in Standard Conditions.