n in the change in free gibbs energy equation


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805329408
Posts: 49
Joined: Wed Nov 20, 2019 12:21 am

n in the change in free gibbs energy equation

Postby 805329408 » Mon Feb 24, 2020 11:14 pm

How do you find n? Is it number of moles of products minus reactants? vice versa? or is it just the change in moles which means it is always positive? thanks in advance!

Ryan Chang 1C
Posts: 105
Joined: Sat Aug 24, 2019 12:17 am

Re: n in the change in free gibbs energy equation

Postby Ryan Chang 1C » Mon Feb 24, 2020 11:54 pm

It's the number of electrons that are reduced/oxidized in the reaction.

Jainam Shah 4I
Posts: 130
Joined: Fri Aug 30, 2019 12:16 am

Re: n in the change in free gibbs energy equation

Postby Jainam Shah 4I » Tue Feb 25, 2020 8:26 pm

It would be the number of electrons that are being transferred. Both the half reactions should be gaining and losing the same amount of electrons depending on which is the reduction half reaction and which is the oxidization half reaction.

KaleenaJezycki_1I
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Joined: Sat Aug 17, 2019 12:18 am
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Re: n in the change in free gibbs energy equation

Postby KaleenaJezycki_1I » Tue Feb 25, 2020 9:20 pm

its the overall change in moles that is always positive, and the equation has a negative in it so it ends up becoming a negative value, when plugged in to the standard gibbs free energy equation.

BCaballero_4F
Posts: 94
Joined: Wed Nov 14, 2018 12:22 am

Re: n in the change in free gibbs energy equation

Postby BCaballero_4F » Tue Feb 25, 2020 9:46 pm

n refers to the moles of electrons so the coefficient in front of the electrons when you balance the half reactions


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