6N1 part b


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705121606
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6N1 part b

Postby 705121606 » Thu Feb 27, 2020 12:24 am

we are asked to calculate the equilibrium constants for the equation using lnk=nE/.02569. I don't understand why n in this case would be 2e- because then I don't believe the charges are balanced, can someone explain this to me

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Re: 6N1 part b

Postby Chem_Mod » Thu Feb 27, 2020 3:50 pm

If you look at the half reactions, you will see that 2e- is needed to balance the positive 2+ charge on Ti 2+ (for reduction) and positive 2+ charge on Mn 2+.


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