delta g

[Ghadir Seder 1G]

Can someone explain why delta g equals 0 when the reaction is at equilibrium?

[Joowon Seo 3A]

Because there is no more free energy to do work when the reaction is at equilibrium because the reaction is at the most stable point.

[Jaci Glassick 2G]

DeltaG is a measure of how much potential a reaction has left to do a net something, so if the reaction is at equilibrium, then no more work can be done and deltaG is 0.

[Justin Quan 4I]

To show why ∆G=0 at equilibrium from a mathematical perspective, use ∆G˚= - RTlnK and ∆G = ∆G˚ + RTlnQ. If we substitute ∆G˚ out, then ∆G = RTlnQ - RTlnK. When the reaction is at equilibrium, the Q=K, thus ∆G = RTlnQ - RTlnK = RTlnK - RTlnK = 0.