6L.1b Ecellº


Moderators: Chem_Mod, Chem_Admin

KDang_1D
Posts: 127
Joined: Fri Aug 30, 2019 12:15 am
Been upvoted: 1 time

6L.1b Ecellº

Postby KDang_1D » Sat Feb 29, 2020 6:39 pm

6Fe^3+(aq) + 2Cr^3+(aq) + 7H2O(l) --> 6Fe^2+(aq) + Cr2O7^2-(aq) + 14H+(aq), Ecellº=-1.29V


I tried calculating the Ecellº on my own for practice and didn't get -1.29V.

From the Appendix:
Fe^3+(aq) --> 6Fe^2+(aq), Eº=+0.77V
Cr2O7^2-(aq) + 14H+(aq) --> 2Cr^3+(aq) + 7H2O(l), Eº=+1.33 V

Wouldn't Eºcell = 0.77 V - 1.33V = -0.56V?

Tyler Angtuaco 1G
Posts: 130
Joined: Wed Sep 11, 2019 12:16 am

Re: 6L.1b Ecellº

Postby Tyler Angtuaco 1G » Sat Feb 29, 2020 6:49 pm

Your calculation should be correct based on the values given on Appendix 2B. I'm not sure either how they got -1.29V.


Return to “Work, Gibbs Free Energy, Cell (Redox) Potentials”

Who is online

Users browsing this forum: No registered users and 2 guests