Problem 6N.1 part b

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Problem 6N.1 part b

Postby nehashetty_2G » Sun Mar 01, 2020 10:59 am

Both the half reactions for In3+/In2+ and U3+/U4+ use only one electron and it balances out correctly. So, why does the solution manual uses 2e- for n?

Luc Zelissen 1K
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Re: Problem 6N.1 part b

Postby Luc Zelissen 1K » Sun Mar 01, 2020 7:26 pm

I believe the solutions manual is wrong.

Rohit Ghosh 4F
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Re: Problem 6N.1 part b

Postby Rohit Ghosh 4F » Tue Mar 10, 2020 3:44 pm

You can find n by balancing the half reactions in a given redox reaction. Because the amount of electrons transferred in oxidation equals the amount transferred in reduction, you can find a single value for n, the number of moles of electrons transferred in total.

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Re: Problem 6N.1 part b

Postby 205405339 » Tue Mar 10, 2020 5:14 pm

yes, if both half reactions only show 1 mole of electrons being transferred then n=1 thus the solution manual is wrong

cassidysong 1K
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Re: Problem 6N.1 part b

Postby cassidysong 1K » Fri Mar 13, 2020 12:10 pm

Yeah I noticed the same error, I think it's just a mistake.

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