6N15.


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505316964
Posts: 95
Joined: Thu Jul 11, 2019 12:17 am

6N15.

Postby 505316964 » Sun Mar 01, 2020 2:17 pm

6N15.
Calculate the potential of a cell constructed with two nickel electrodes. The electrolyte in one compartment is 1.0 m Ni(NO3)2(aq). In the other compartment, NaOH has been added to a Ni(NO3)2 solution until the pH 5 11.0 at 298 K. See Table 6I.1.

I calculated this by assuming it's a concentration cell and I got 0.3V for E which is the answer in the back of the book.
I didn't use Table 6I.1 at all. Is it a coincidence that I got the correct answer without using Ksp values?

Ritu Gaikwad 2E
Posts: 52
Joined: Thu Jul 11, 2019 12:16 am

Re: 6N15.

Postby Ritu Gaikwad 2E » Sun Mar 01, 2020 8:05 pm

I don't think it is a coincidence because there is the same species in both cells so it would make sense to assume a concentration cell.

Lindsey Chheng 1E
Posts: 110
Joined: Fri Aug 30, 2019 12:16 am

Re: 6N15.

Postby Lindsey Chheng 1E » Mon Mar 02, 2020 10:08 pm

505316964 wrote:6N15.
Calculate the potential of a cell constructed with two nickel electrodes. The electrolyte in one compartment is 1.0 m Ni(NO3)2(aq). In the other compartment, NaOH has been added to a Ni(NO3)2 solution until the pH 5 11.0 at 298 K. See Table 6I.1.

I calculated this by assuming it's a concentration cell and I got 0.3V for E which is the answer in the back of the book.
I didn't use Table 6I.1 at all. Is it a coincidence that I got the correct answer without using Ksp values?

Can I ask how you were able to calculate it?


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