N value

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N value

Postby Andrea_Torres » Sun Mar 01, 2020 5:23 pm

I know that n is the electrons but is it the one that is shown on the reactions when it says for example 2e-? Would the n be 2 in that case?

John Liang 2I
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Re: N value

Postby John Liang 2I » Sun Mar 01, 2020 5:24 pm

N is the number of moles of e- transferred. So yes, N equals the coefficient of the e- in the equation.

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Re: N value

Postby Owen-Koetters-4I » Sun Mar 01, 2020 6:25 pm

N is the number of mol of electrons transferred.

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Re: N value

Postby zfinn » Sun Mar 01, 2020 6:32 pm

yep! unless one half reaction has 2e- and the other has 4e-, then n=4 because it is the lowest common multiple.

kendal mccarthy
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Re: N value

Postby kendal mccarthy » Sun Mar 01, 2020 10:33 pm

yes, you must balance both half-reactions to see if the electrons exchanged is the same, and if not multiply by a coefficient so they cancel out when they are added together to create the full balanced reaction. This value that cancels is your n.

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Re: N value

Postby JesseAuLec1Dis1G » Sun Mar 01, 2020 10:37 pm

You just half to make sure that the number of electrons cancel out in both of the half reactions. But to answer your question yes it would be 2.

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Re: N value

Postby Martina » Sun Mar 01, 2020 11:33 pm

You have to balance the reduction and oxidation half reactions and then see how many electrons are added in order to balance the charges. The number of electrons is the n value.

Alexandra Bartolome 2H
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Re: N value

Postby Alexandra Bartolome 2H » Mon Mar 02, 2020 12:49 am

Yes, 2 would be n since n is the number of electrons being transferred, but make sure your half-reactions are balanced!

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