N value


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Andrea_Torres
Posts: 98
Joined: Sun Sep 15, 2019 12:15 am

N value

Postby Andrea_Torres » Sun Mar 01, 2020 5:23 pm

I know that n is the electrons but is it the one that is shown on the reactions when it says for example 2e-? Would the n be 2 in that case?

John Liang 2I
Posts: 102
Joined: Fri Aug 30, 2019 12:18 am

Re: N value

Postby John Liang 2I » Sun Mar 01, 2020 5:24 pm

N is the number of moles of e- transferred. So yes, N equals the coefficient of the e- in the equation.

Owen-Koetters-4I
Posts: 50
Joined: Fri Sep 28, 2018 12:16 am

Re: N value

Postby Owen-Koetters-4I » Sun Mar 01, 2020 6:25 pm

N is the number of mol of electrons transferred.

zfinn
Posts: 106
Joined: Fri Aug 30, 2019 12:16 am

Re: N value

Postby zfinn » Sun Mar 01, 2020 6:32 pm

yep! unless one half reaction has 2e- and the other has 4e-, then n=4 because it is the lowest common multiple.

kendal mccarthy
Posts: 109
Joined: Wed Nov 14, 2018 12:22 am

Re: N value

Postby kendal mccarthy » Sun Mar 01, 2020 10:33 pm

yes, you must balance both half-reactions to see if the electrons exchanged is the same, and if not multiply by a coefficient so they cancel out when they are added together to create the full balanced reaction. This value that cancels is your n.

JesseAuLec1Dis1G
Posts: 52
Joined: Mon Jun 17, 2019 7:23 am

Re: N value

Postby JesseAuLec1Dis1G » Sun Mar 01, 2020 10:37 pm

You just half to make sure that the number of electrons cancel out in both of the half reactions. But to answer your question yes it would be 2.

Martina
Posts: 111
Joined: Thu Jul 25, 2019 12:16 am

Re: N value

Postby Martina » Sun Mar 01, 2020 11:33 pm

You have to balance the reduction and oxidation half reactions and then see how many electrons are added in order to balance the charges. The number of electrons is the n value.

Alexandra Bartolome 2H
Posts: 102
Joined: Sat Jul 20, 2019 12:17 am

Re: N value

Postby Alexandra Bartolome 2H » Mon Mar 02, 2020 12:49 am

Yes, 2 would be n since n is the number of electrons being transferred, but make sure your half-reactions are balanced!


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