## delta G=-nFE

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

205389184
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### delta G=-nFE

If the n in DeltaG=-nFE is not explicitly given, how do we calculate its value?

Andrew Pfeiffer 2E
Posts: 101
Joined: Sat Sep 28, 2019 12:16 am

### Re: delta G=-nFE

We can calculate it if we have all the other components of this equation (the standard change in Gibbs free energy, the energy, and Faraday's constant). Otherwise, we must use additional equations and knowledge about the conditions to indirectly solve for n and plug it back in.

Jasmine Vallarta 2L
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Joined: Sat Aug 17, 2019 12:18 am

### Re: delta G=-nFE

you can try to find the half rxns

Posts: 52
Joined: Thu Jul 11, 2019 12:16 am

### Re: delta G=-nFE

If the n is not given, look at the half reactions and find the number of moles of electrons transferred and that is your n value because that is what n stands for in the equation.

Shimei_2F
Posts: 100
Joined: Fri Aug 09, 2019 12:17 am

### Re: delta G=-nFE

You can find it by balancing the electrons of the half-reactions and that's the n, the amount in moles of electrons that were transferred.

saigorijavolu2k
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Joined: Sat Sep 28, 2019 12:15 am

### Re: delta G=-nFE

You balance the half reactions and find out how many electrons are transferred.

Tahlia Mullins
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Joined: Thu Jul 25, 2019 12:15 am

### Re: delta G=-nFE

If n is not given, you can go through the process of balancing the half reactions for oxidation and reduction, eventually finding the number of moles of electrons being transferred!

AronCainBayot2K
Posts: 101
Joined: Fri Aug 30, 2019 12:17 am

### Re: delta G=-nFE

You can calculate n whether by the other information given, such as Gibbs Free Energy, or using the half reactions to determine the amount of electrons.

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