n in Equation


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905373636
Posts: 62
Joined: Thu Aug 01, 2019 12:15 am

n in Equation

Postby 905373636 » Sun Mar 01, 2020 11:40 pm

I'm a bit confused as to how to find n in reactions and I'm a bit confused too with what it represents.

For example,
for the reaction Mn + Ti2+ <--> Mn2+ + Ti n=2, but I'm not sure as to why.

Could someone help explain?

Naji Sarsam 1F
Posts: 104
Joined: Sat Aug 17, 2019 12:18 am

Re: n in Equation

Postby Naji Sarsam 1F » Sun Mar 01, 2020 11:46 pm

n represents the moles of electrons transferred in a redox reaction. To know how many electrons are transferred, you have to divide a redox reaction into its reduction and oxidation half-reactions.

JustinHorriat_4f
Posts: 111
Joined: Wed Sep 18, 2019 12:19 am

Re: n in Equation

Postby JustinHorriat_4f » Sun Mar 01, 2020 11:46 pm

n is the number of electrons so you would divide the rxn into half rxns and see how many electrons are being transferred and thats your n. In this case it is 2.

Kevin Antony 2B
Posts: 99
Joined: Sat Sep 07, 2019 12:16 am

Re: n in Equation

Postby Kevin Antony 2B » Sun Mar 01, 2020 11:49 pm

When you look at the individual half reactions, n represents the moles of electrons being transferred. This value must be the same for both half reactions.

Emil Velasco 1H
Posts: 96
Joined: Wed Nov 21, 2018 12:19 am

Re: n in Equation

Postby Emil Velasco 1H » Sun Mar 01, 2020 11:53 pm

Look for the number of electrons being transferred between the half reactions

Alexandra Bartolome 2H
Posts: 102
Joined: Sat Jul 20, 2019 12:17 am

Re: n in Equation

Postby Alexandra Bartolome 2H » Mon Mar 02, 2020 12:28 am

In the equation, n is the number of electrons in moles that is being transferred.

Sanjana K - 2F
Posts: 102
Joined: Sat Sep 07, 2019 12:17 am
Been upvoted: 1 time

Re: n in Equation

Postby Sanjana K - 2F » Mon Mar 02, 2020 12:30 am

One thing to remember is that you should always take the balanced number of moles of electrons for the reaction as your value of n.


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