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Postby MariaJohn1D » Mon Mar 02, 2020 5:15 pm

Why do we flip the reducing agent in the cell notation for this question?

Alexis Webb 2B
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Re: 6M.11

Postby Alexis Webb 2B » Mon Mar 02, 2020 8:28 pm

Which part of the question are you referring to?

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Re: 6M.11

Postby haileyramsey-1c » Tue Mar 03, 2020 4:23 pm

If you are asking about flipping the sign of the reducing agent then that happens because the reducing agent is the substance being oxidized. In the book they use Ecell=Ecathode+Eanode, so you flip the sign of the thing being oxidized because it is the reverse reaction, but in class Lavelle went over subtracting not adding. Either way works but you have to just pick one.

Sean Cheah 1E
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Re: 6M.11

Postby Sean Cheah 1E » Wed Mar 04, 2020 11:25 am

The standard convention is to list standard reduction potentials, meaning the E values for the reduction reactions. If you are dealing with an oxidation half-reaction (the reverse of the reduction half-reaction), you typically have to negate the given E value.

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