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### finding n in G=-nFE

Posted: Thu Mar 05, 2020 2:36 am
How do you find n?

### Re: finding n in G=-nFE

Posted: Thu Mar 05, 2020 8:20 am
n is the number of electron transferred which can be found when you balance the redox reaction.

### Re: finding n in G=-nFE

Posted: Thu Mar 05, 2020 9:31 am
When you find the half reactions, n is the least common multiple of their shared electrons. So you would have to balance them. (Usually n is either 1 or 2).

### Re: finding n in G=-nFE

Posted: Thu Mar 05, 2020 10:19 am
You can find n when you are balancing your redox reaction. n is the moles of electrons being transferred in the balanced reaction.

### Re: finding n in G=-nFE

Posted: Thu Mar 05, 2020 10:26 am
When you write and balance the half-reactions, the mols of electrons (should be balanced to be the same in both equations) is the number you use as n in the equation.

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 11:19 am
To find n you balance the redox reaction to determine the number of moles of electrons being transferred during the reaction.

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 11:37 am
For example in a redox eq like Cu2+ + 2e- ---> Cu, n would be 2 since 2 electrons sre being transferred.

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 1:38 pm
After you balance the redox reaction, the number of electrons in the overall reaction is n.

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 7:26 pm
n is the number of electrons exchanged in the general reaction. So you look at the oxidation numbers, and then you look at how they have changed.

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 7:53 pm
use the highest number of moles of electrons transferred according to the half reactions

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 8:31 pm
You need to write out the half reactions first. When you combine the half reactions, n is the number of electrons on either side of the equation (they cancel each other out).

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 9:38 pm
n is the number of electrons being transferred in the redox equation.

### Re: finding n in G=-nFE

Posted: Sat Mar 07, 2020 11:08 pm
Hannah_1G wrote:How do you find n?

"n" is found by finding the two half reactions, and balancing them.
When balancing the half reactions, in order to balance the two half reaction charges, you will add electrons. The number of electrons in the reaction is the value of "n".

### Re: finding n in G=-nFE

Posted: Sun Mar 08, 2020 12:33 am
n is the number of electrons transferred in a redox reaction.

### Re: finding n in G=-nFE

Posted: Sun Mar 08, 2020 10:56 am
you can find n after balancing the half rxns. the number of e- should cancel out and that number = n

### Re: finding n in G=-nFE

Posted: Sun Mar 08, 2020 11:23 pm
"n" is the number of balanced electrons on both sides.