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### Units G=-nFE

Posted: Fri Mar 06, 2020 8:17 am
I'm not sure if this is common sense, but if the units for F are coulombs and the units for E are volts, how do we get joules for G?

### Re: Units G=-nFE

Posted: Fri Mar 06, 2020 9:44 am
The units cancel out because volts, coulombs, and joules are all interrelated -- one joule is equal to one volt times one coulomb.

### Re: Units G=-nFE

Posted: Fri Mar 06, 2020 10:32 am
The units of Volts are actually equivalent to Joules/Coulomb. So, if you work out the math, the units should all cancel and you will get Joules.

### Re: Units G=-nFE

Posted: Fri Mar 06, 2020 1:01 pm
1 Volt = 1 J/C so the units cancel out when you multiply;

substituting the units in for -nFE, you get
-(mol)x(C/mol)x(V=J/C), and you’re left with J for G

### Re: Units G=-nFE

Posted: Fri Mar 06, 2020 3:15 pm
Volts = Joules/Coulomb so in deltaG=-nFE the Coulombs cancel out from the multiplication between E (J/C) and F (C/mol), and n has no units so the final units will be J/mol.

### Re: Units G=-nFE

Posted: Fri Mar 06, 2020 8:31 pm
F is also Coulombs/mol and Volts is Joules/Coulomb. When multiplied together, the units cancel out leaving Joules for deltaG

### Re: Units G=-nFE

Posted: Fri Mar 06, 2020 9:10 pm
Zaynab Hashm 2I wrote:1 Volt = 1 J/C so the units cancel out when you multiply;

substituting the units in for -nFE, you get
-(mol)x(C/mol)x(V=J/C), and you’re left with J for G

Does n have units? I have seen some TAs and UAs write mole of e- when plugging in the numbers into n in that equation. But I have also heard that n does not have units and that is why we end up with J/mol as our final units for delta G. Could someone clarify this for me, please?