G=-nFe
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G=-nFe
I know that in the G=-nFe equation, n is the number of electrons transferred. Does that mean the electrons transferred from 1 compound to another? I'm confused because in a lot of equations, everything rearranges from one side to the other...
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Re: G=-nFe
n indicates the number of electrons that are involved in the transfer between the oxidizing agent and reducing agent. When you have your two half-reactions for OX and RED, you have to balance your electrons to make sure your electron transfer is balanced out. The balanced value of electrons is what you use for the n value. This forum's https://chemistry.stackexchange.com/questions/5122/how-is-it-determined-how-many-electrons-are-transferred-in-redox-reactions top answer does a good job explaining this!
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Re: G=-nFe
n is the number of electrons transferred and can be seen in the half reactions when balanced. Since your redox half reactions are balanced, the number of electrons given off should be the same for both half-reactions.
Re: G=-nFe
Yes, you basically just need to know that however many electrons you have in your overall balanced equation will be plugged into n.
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Re: G=-nFe
The way I do it is however many electrons are in your balanced equation after you multiply and match the coefficients.
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Re: G=-nFe
n is the number of electrons transferred in the redox equation. When you do your reduction half reaction there is a certain amount of electrons transferred and same case for the oxidation half reaction. You then have to multiply the equations to balance the electrons. when they match and cancel that number is n
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Re: G=-nFe
You have to look at the number of electrons transferred in the redox reaction. (Essentially, the number of electrons that balances the combined half-reactions.)
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