## Battery

$\Delta G^{\circ} = -nFE_{cell}^{\circ}$

Michael Du 1E
Posts: 117
Joined: Sun Sep 22, 2019 12:16 am

### Battery

Just for clarification, a dead battery means that the E potential is 0 right, also implying that Delta G is 0? Thank you

Selena Yu 1H
Posts: 108
Joined: Fri Aug 09, 2019 12:16 am

### Re: Battery

Yes, a dead battery means that the reaction is at equilibrium so E potential is 0 and so is delta G.

Brianna Becerra 1B
Posts: 117
Joined: Fri Aug 02, 2019 12:16 am

### Re: Battery

Yes, that is correct. This is because, at equilibrium, there is no E change. In turn, G=-nFE and since E is zero, G is as well.

JohnWalkiewicz2J
Posts: 103
Joined: Thu Jul 11, 2019 12:17 am
Been upvoted: 1 time

### Re: Battery

Yes when the cell potential is 0, and given the deltaG = -nFE, gibbs free energy would also be zero, and the battery is dead! :D

Long Luong 2H
Posts: 51
Joined: Thu Sep 19, 2019 12:16 am

### Re: Battery

Yes, conceptually, there is no difference in electric potential between two cells so no electrons are being transferred between them. If the difference in electric potential is zero, no work can be done.

Rodrigo2J
Posts: 102
Joined: Sat Jul 20, 2019 12:16 am

### Re: Battery

Yes, at equilibrium we know that delta G and E both equal 0.

Tanmay Singhal 1H
Posts: 143
Joined: Sat Jul 20, 2019 12:16 am

### Re: Battery

yes thus meaning it can do no work

Daniela Shatzki 2E
Posts: 53
Joined: Sat Aug 24, 2019 12:16 am

### Re: Battery

Yes because if it is dead it is not spontaneous so delta G = 0

vanessas0123
Posts: 100
Joined: Wed Sep 11, 2019 12:17 am

### Re: Battery

A dead battery means that the reaction is at equilibrium, so Ecell and delta G is 0.