I cannot seem to balance this equation correctly and I feel like I'm doing the process right. Can anyone help me out or tell me how they got their answer?
N2H4 (g) + ClO3- --> NO(g) + Cl- (aq)
The balanced half reactions I got were:
N2H4 + 8OH- --> 2NO + 6H2O + 8e-
ClO3- + 6e- --> Cl- + 6OH-
But I keep getting the final answer incorrect.
Sapling Week 7/8 #5 pt. 2
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 100
- Joined: Wed Sep 30, 2020 9:35 pm
Re: Sapling Week 7/8 #5 pt. 2
Hey everything looks right but you are missing the three H2O molecules you should have left over from balancing the oxygens on the left side of the ClO3- to Cl- half reaction. Once you include these H2O molecules you should be good!
-
- Posts: 51
- Joined: Wed Nov 18, 2020 12:30 am
- Been upvoted: 1 time
Re: Sapling Week 7/8 #5 pt. 2
I had the same problem. I kept forgetting to include the H2O's. But as the previous reply mentioned, adding the H2O should fix your error.
-
- Posts: 103
- Joined: Wed Feb 26, 2020 12:17 am
-
- Posts: 52
- Joined: Wed Dec 02, 2020 12:19 am
Re: Sapling Week 7/8 #5 pt. 2
The second one is wrong as it should be what I wrote below:
ClO3- + 6e- + 3H2O → Cl- + 6OH-
Hope this helps you just forgot the H2O.
ClO3- + 6e- + 3H2O → Cl- + 6OH-
Hope this helps you just forgot the H2O.
Re: Sapling Week 7/8 #5 pt. 2
Looks like you just need to add 3 H2O molecules to the left side of your second equation
-
- Posts: 103
- Joined: Wed Sep 30, 2020 9:59 pm
Re: Sapling Week 7/8 #5 pt. 2
Hi! It seems like you just need to add more H20 molecules to the left side of the reaction :)
Return to “Work, Gibbs Free Energy, Cell (Redox) Potentials”
Who is online
Users browsing this forum: No registered users and 8 guests