Sapling Week 7/8 #5 pt. 2


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Shannon Moore 2L
Posts: 103
Joined: Wed Feb 26, 2020 12:17 am

Sapling Week 7/8 #5 pt. 2

Postby Shannon Moore 2L » Sun Feb 28, 2021 2:15 pm

I cannot seem to balance this equation correctly and I feel like I'm doing the process right. Can anyone help me out or tell me how they got their answer?

N2H4 (g) + ClO3- --> NO(g) + Cl- (aq)

The balanced half reactions I got were:

N2H4 + 8OH- --> 2NO + 6H2O + 8e-
ClO3- + 6e- --> Cl- + 6OH-

But I keep getting the final answer incorrect.

Blake Ballew 1H
Posts: 100
Joined: Wed Sep 30, 2020 9:35 pm

Re: Sapling Week 7/8 #5 pt. 2

Postby Blake Ballew 1H » Sun Feb 28, 2021 2:31 pm

Hey everything looks right but you are missing the three H2O molecules you should have left over from balancing the oxygens on the left side of the ClO3- to Cl- half reaction. Once you include these H2O molecules you should be good!

Irene Chang 2F
Posts: 51
Joined: Wed Nov 18, 2020 12:30 am
Been upvoted: 1 time

Re: Sapling Week 7/8 #5 pt. 2

Postby Irene Chang 2F » Sun Feb 28, 2021 11:57 pm

I had the same problem. I kept forgetting to include the H2O's. But as the previous reply mentioned, adding the H2O should fix your error.

Shannon Moore 2L
Posts: 103
Joined: Wed Feb 26, 2020 12:17 am

Re: Sapling Week 7/8 #5 pt. 2

Postby Shannon Moore 2L » Sun Mar 14, 2021 5:59 pm

Thanks guys!!

Levon Grigoryan
Posts: 52
Joined: Wed Dec 02, 2020 12:19 am

Re: Sapling Week 7/8 #5 pt. 2

Postby Levon Grigoryan » Sun Mar 14, 2021 10:08 pm

The second one is wrong as it should be what I wrote below:
ClO3- + 6e- + 3H2O → Cl- + 6OH-

Hope this helps you just forgot the H2O.

Samir 3I
Posts: 53
Joined: Wed Sep 30, 2020 10:04 pm

Re: Sapling Week 7/8 #5 pt. 2

Postby Samir 3I » Sun Mar 14, 2021 11:29 pm

Looks like you just need to add 3 H2O molecules to the left side of your second equation

Daniela Santana 2L
Posts: 103
Joined: Wed Sep 30, 2020 9:59 pm

Re: Sapling Week 7/8 #5 pt. 2

Postby Daniela Santana 2L » Mon Mar 15, 2021 11:00 pm

Hi! It seems like you just need to add more H20 molecules to the left side of the reaction :)


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