R constant


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Kiran Marla
Posts: 50
Joined: Wed Nov 18, 2020 12:25 am

R constant

Postby Kiran Marla » Thu Mar 11, 2021 8:39 pm

How do I know which R to use in the equation deltaG=deltaGnought + RTlnQ

HannahRobinson3L
Posts: 101
Joined: Wed Sep 30, 2020 9:51 pm
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Re: R constant

Postby HannahRobinson3L » Thu Mar 11, 2021 8:41 pm

You'd want to use the value 8.314 J*K^-1*mol^-1 for this equation. The easiest way to tell is to look at the units of everything else in the equation and see what needs to be cancelled. Hope this helps.

Eliana Witham 2H
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Re: R constant

Postby Eliana Witham 2H » Thu Mar 11, 2021 8:44 pm

You use R= 8.314 J/(Kmol). If you look at the units, we know that delta G and delta G nought are in J/mol. Therefore, RTlnQ needs to be in J/mol, too. When R is in J/(Kmol) and temperature is K, then the final product of RxT is in J/mol, which is what you want.

derickngo3d
Posts: 111
Joined: Wed Sep 30, 2020 9:51 pm

Re: R constant

Postby derickngo3d » Thu Mar 11, 2021 9:17 pm

Usually, look for whetehr Joules are used in the question, and that would mean that you would use 8.314 J/(K x mol.)

Jiapeng Han 1C
Posts: 101
Joined: Wed Sep 30, 2020 9:50 pm

Re: R constant

Postby Jiapeng Han 1C » Fri Mar 12, 2021 5:06 am

Typically 8.314JK^-1mol^-1 is used, but it really depends on the units of other variables that are given.

Muskaan Abdul-Sattar
Posts: 101
Joined: Wed Nov 13, 2019 12:19 am

Re: R constant

Postby Muskaan Abdul-Sattar » Sun Mar 14, 2021 9:44 pm

Typically, to determine what value of R to use, you look at the units being used. In this scenario, R would equal 8.314 J/(Kmol)!

Taha 2D
Posts: 100
Joined: Wed Sep 30, 2020 9:50 pm

Re: R constant

Postby Taha 2D » Sun Mar 14, 2021 9:48 pm

it will depend on the units given to you in the question. you can use either but its more efficient to use the one matching the questions units so you wont have to convert anything


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