Finding K


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Alex Nguyen 3I
Posts: 100
Joined: Fri Sep 25, 2015 3:00 am

Finding K

Postby Alex Nguyen 3I » Fri Feb 05, 2016 9:32 pm

To find K, I used E not=RT/nF(lnK) in order to find K. However, when I used log K=n*E not/0.0592, the answer was different. Is this right? If so, which equation should be used?

fourmethylhexane
Posts: 9
Joined: Wed Nov 11, 2015 3:00 am

Re: Finding K

Postby fourmethylhexane » Sat Feb 06, 2016 11:32 am

for this instance,the disparity in your answers might arise from what you use as R in RT. Furthermore, the 0.0592 is an approximation for accounting from the change in equation format from Ln(K)=(nF)/(RT)(Enot) to Log(K)=(n*Enot)/0.0592. Thus, your answers would vary slightly depending on which equation is used, but should not be a drastic difference.


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