E Naught of cell
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E Naught of cell
Does the E naught of cell change when using Hess's law and if it does not what is the reason behind it
Re: E Naught of cell
When using Hess's law to determine the standard cell potential (E°cell), the E°cell does not change. This is because Hess's law states that the overall change in enthalpy (ΔH) for a reaction is the same regardless of the route taken to achieve the final products from the initial reactants. Similarly, E°cell represents the overall tendency for electrons to flow from the anode to the cathode and is determined by the standard reduction potentials of the half-reactions involved, which do not change with the path taken to reach the final state. Therefore, E°cell remains constant when using Hess's law.
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Re: E Naught of cell
The E naught of the cell holistically describes a balanced reaction of two reactants instead of the formation or change of one particular substance. Hence, I do not think that Hess's Law is applicable to, say, calculate the E naught of a redox reaction between iron and copper.
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Re: E Naught of cell
Hi! The value of E naught remains relatively unchanged. The only time you "flip" the value is when you flip the anode when you have to reverse the reaction so you would be subtracting a negative, or adding. However, the factors that affect E naught temperature, concentration, and pressure. Hope this helps!
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Re: E Naught of cell
Since E0 is an intensive property, the stoichiometric coefficients do not affect the value E0, so Hess' Law doesn't really apply to E0. Rather, the only thing that can be changed on E0 is the sign to reflect whether or not it is the reduction potential or the oxidization potential.
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