Ch 14 Exercise 43


Moderators: Chem_Mod, Chem_Admin

Ariana_Kermani_2G
Posts: 10
Joined: Fri Jul 15, 2016 3:00 am

Ch 14 Exercise 43

Postby Ariana_Kermani_2G » Wed Feb 08, 2017 9:56 pm

A tin electrode in 0.015M Sn(NO3)2 (aq) is connected to a hydrogen electrode in which the pressure of H2 is 1.0 bar. If the cell potential is 0.061 V at 25 degrees Celsius, what is the pH of the electrolyte at the hydrogen electrode?

Which equation are we supposed to use to solve this problem?

Thanks!

Arshia_Sabir_3E
Posts: 13
Joined: Wed Sep 21, 2016 2:59 pm

Re: Ch 14 Exercise 43

Postby Arshia_Sabir_3E » Thu Feb 09, 2017 9:34 am

Use the Nernst equation in order to calculate the PH of the electrolyte at the hydrogen electrode.
You can start with E=E(node)-(0.0256V/n) ln([Sn^2]/[H^+]^2) and Just solve for the concentration of [H^+]^2.
Then convert that concentration to PH by -log([H^+]

Hope this helps!


Return to “Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)”

Who is online

Users browsing this forum: No registered users and 1 guest