## hw:14.107 Relation of K and H+/OH-

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Yinhan_Liu_1D
Posts: 51
Joined: Sat Sep 24, 2016 3:00 am

### hw:14.107 Relation of K and H+/OH-

I don't quite understand why we use K=[H+]/[OH-]

Are we using H2O->H+ + OH-? Then why aren't they both in the [product] part?

Or there is another RXN?

Aneesh_Gowri 1H
Posts: 21
Joined: Wed Sep 21, 2016 2:59 pm

### Re: hw:14.107 Relation of K and H+/OH-

In some galvanic cells, the reaction H2O -> H + OH is part of the oxidation/reduction reaction. So the H+ is part of the reduction reaction at the cathode and the OH- is part of the oxidation reaction at the anode.

At the end, after you solve the problem, you'll end up with H + OH -> H2O as the final reaction

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