## Nernst Equation at 25 degrees? [ENDORSED]

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Franklin Kong 3D
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Joined: Fri Jul 22, 2016 3:00 am
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### Nernst Equation at 25 degrees?

On the bottom of Page 51 of the Course Reader, it displays the Nernst Equation. Then, on the next page, it says that at 25 degrees Celsius, it has 2.303RT/F = 0.059V, then E (cell) = E (standard) - 0.0592 / n Log (10) Q. Where did the "2.303" come from? And shouldn't it be lnQ as it is in the Nernst Equation instead of Log (10) Q?

Yi Ying Chen 3N
Posts: 13
Joined: Wed Sep 21, 2016 2:55 pm

### Re: Nernst Equation at 25 degrees?  [ENDORSED]

The "2.303" comes from writing the Nernst equation in log base 10 rather than in ln:

$lnQ = \frac{logQ}{loge} = \frac{logQ}{\frac{lne}{ln10}} = ln10\times logQ = 2.303logQ$

It's sometimes more convenient to use log base 10, like when you're dealing with pH.

Return to “Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)”

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