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### Nernst Equation at 25 degrees?

Posted: Sat Feb 11, 2017 11:31 pm
On the bottom of Page 51 of the Course Reader, it displays the Nernst Equation. Then, on the next page, it says that at 25 degrees Celsius, it has 2.303RT/F = 0.059V, then E (cell) = E (standard) - 0.0592 / n Log (10) Q. Where did the "2.303" come from? And shouldn't it be lnQ as it is in the Nernst Equation instead of Log (10) Q?

### Re: Nernst Equation at 25 degrees?  [ENDORSED]

Posted: Sat Feb 11, 2017 11:49 pm
The "2.303" comes from writing the Nernst equation in log base 10 rather than in ln:

$lnQ = \frac{logQ}{loge} = \frac{logQ}{\frac{lne}{ln10}} = ln10\times logQ = 2.303logQ$

It's sometimes more convenient to use log base 10, like when you're dealing with pH.