Winter 2013 Midterm 8B

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Winter 2013 Midterm 8B

Postby Niveda_Tennety_1H » Tue Feb 14, 2017 1:46 pm

For Q8B on the Winter 2013 Midterm, how is n 8? Where are the electrons being transferred in this equation?: Fe(s) (+) 2Ce4+ -->Fe2+ (+) 2Ce3+

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Re: Winter 2013 Midterm 8B

Postby Sarah_Heesacker_3B » Tue Feb 14, 2017 2:06 pm

In that question, n is actually equal to 2. The half reactions are Fe2+(aq) +2e- --> Fe(s) and Ce4+(aq) + 1e- --> Ce3+(aq). So when the equations are balanced the number of electrons in each equation is 2, which is why n=2.

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