## Winter 2013 Midterm 8B

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Niveda_Tennety_1H
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Joined: Wed Sep 21, 2016 2:59 pm

### Winter 2013 Midterm 8B

For Q8B on the Winter 2013 Midterm, how is n 8? Where are the electrons being transferred in this equation?: Fe(s) (+) 2Ce4+ -->Fe2+ (+) 2Ce3+

Sarah_Heesacker_3B
Posts: 21
Joined: Wed Sep 21, 2016 2:57 pm

### Re: Winter 2013 Midterm 8B

In that question, n is actually equal to 2. The half reactions are Fe2+(aq) +2e- --> Fe(s) and Ce4+(aq) + 1e- --> Ce3+(aq). So when the equations are balanced the number of electrons in each equation is 2, which is why n=2.

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