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Posted: Mon Feb 19, 2018 11:13 am
by Elizabeth Ignacio 1C
One of half reactions needed to calculate the overall cell potential in 14.23A is 2Hg -> Hg22+ + 2e- and the cell potential for the reverse reaction in the textbook is listed as +0.79, which the solutions manual uses in the calculations for Eocell. I'm confused why they didn't flip the cell potential to get -0.79 if the positive version was the reverse of the reaction that was actually happening.

Re: 14.23A

Posted: Mon Feb 19, 2018 12:38 pm
by manasa933
I'm not really sure why but my TA said that we don't flip potentials because the redox couple is the same.