14.37


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siannehazel1B
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

14.37

Postby siannehazel1B » Mon Feb 19, 2018 5:43 pm

I understand how to plug all the values into the NERNST equation after I write the half reactions, but I'm confused as to where the solutions manual is getting 0.025693V/n. I thought we were supposed to use either 2.303RT/nF or 0.0592/n?

Matthew Lin 2C
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

Re: 14.37

Postby Matthew Lin 2C » Mon Feb 19, 2018 8:35 pm

The equations that you mentioned (2.303RT/nF and 0.0592/n) is with LOG of Q while the solution manual uses LN of Q. Therefore, all three of these equations are actually equivalent. Hope that clarifies it!

McKenna disc 1C
Posts: 60
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.37

Postby McKenna disc 1C » Wed Feb 21, 2018 4:28 pm

siannehazel1B wrote:I understand how to plug all the values into the NERNST equation after I write the half reactions, but I'm confused as to where the solutions manual is getting 0.025693V/n. I thought we were supposed to use either 2.303RT/nF or 0.0592/n?


.025693 V is R * 298.15 K / F.


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