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### 14.37

Posted: **Mon Feb 19, 2018 5:43 pm**

by **siannehazel1B**

I understand how to plug all the values into the NERNST equation after I write the half reactions, but I'm confused as to where the solutions manual is getting 0.025693V/n. I thought we were supposed to use either 2.303RT/nF or 0.0592/n?

### Re: 14.37

Posted: **Mon Feb 19, 2018 8:35 pm**

by **Matthew Lin 2C**

The equations that you mentioned (2.303RT/nF and 0.0592/n) is with LOG of Q while the solution manual uses LN of Q. Therefore, all three of these equations are actually equivalent. Hope that clarifies it!

### Re: 14.37

Posted: **Wed Feb 21, 2018 4:28 pm**

by **McKenna disc 1C**

siannehazel1B wrote:I understand how to plug all the values into the NERNST equation after I write the half reactions, but I'm confused as to where the solutions manual is getting 0.025693V/n. I thought we were supposed to use either 2.303RT/nF or 0.0592/n?

.025693 V is R * 298.15 K / F.