## 14.47 a

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Emily Duggan 1F
Posts: 42
Joined: Fri Sep 29, 2017 6:07 am

### 14.47 a

Hi I understand how ln Q = (about) 15, but how does that mean Q = 10^6?

Cam Bear 2F
Posts: 60
Joined: Thu Jul 27, 2017 2:01 am

### Re: 14.47 a

Yeah, I am stuck on this too. Maybe it's a typo? I can't seem to figure out how they would get 10^6.

Ammarah 2H
Posts: 30
Joined: Fri Sep 29, 2017 6:06 am

### Re: 14.47 a

I was stuck too and I keep getting 2649813.982. Is that what you’re getting as well?

McKenna disc 1C
Posts: 60
Joined: Fri Sep 29, 2017 6:04 am

### Re: 14.47 a

Ammarah 2H wrote:I was stuck too and I keep getting 2649813.982. Is that what you’re getting as well?

The value you're writing here is 2.65 x 10^6, I don't know if that clarifies anything because the problem isn't written here and I don't have my book in front of me so I'm coming at this out of context haha but I hope that helps a little?

Justin Chu 1G
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Joined: Thu Jul 13, 2017 2:00 am
Been upvoted: 1 time

### Re: 14.47 a

You get the right answer if you use the logQ equation instead of the lnQ equation but I have no idea why it would matter either way.

Virpal Gill 1B
Posts: 32
Joined: Thu Jul 27, 2017 2:00 am

### Re: 14.47 a

Ammarah 2H wrote:I was stuck too and I keep getting 2649813.982. Is that what you’re getting as well?

Yeah I'm getting the same answer.

McKenna disc 1C
Posts: 60
Joined: Fri Sep 29, 2017 6:04 am

### Re: 14.47 a

Justin Chu 1G wrote:You get the right answer if you use the logQ equation instead of the lnQ equation but I have no idea why it would matter either way.

Yeah I'm kind of confused about why exactly we'd need to use one equation rather than the other? The only guess I have is like if we're finding hydrogen ion concentration or something like that?

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