14.31


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Wenting Hu 2H
Posts: 33
Joined: Fri Sep 29, 2017 7:06 am

14.31

Postby Wenting Hu 2H » Tue Feb 20, 2018 10:17 pm

for 14.31 how do we determine if the reaction has k>1? Is it cathode/anode?

Samantha Kan 2L
Posts: 30
Joined: Sat Jul 22, 2017 3:00 am

Re: 14.31

Postby Samantha Kan 2L » Tue Feb 20, 2018 10:19 pm

You use E(cathode)-E(anode) to find the standard E. If E is positive, it favors the products so k>1.

Luke Bricca 1H
Posts: 30
Joined: Fri Sep 29, 2017 7:06 am

Re: 14.31

Postby Luke Bricca 1H » Wed Feb 21, 2018 8:50 pm

Furthermore, you could also solve the Nernst equation for K which would show its sign. This would be more work and is inefficient but guarantees a correct answer.

Phillip Winters 2F
Posts: 50
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.31

Postby Phillip Winters 2F » Thu Feb 22, 2018 11:48 pm

Also if K>1, meaning that E>1 as well, then the reaction would be spontaneous in the forward direction

Ashley Macabasco 2K
Posts: 30
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.31

Postby Ashley Macabasco 2K » Fri Feb 23, 2018 1:04 am

If E(cathode)>E(anode) then K>1 and products are favored.

Matthew Lee 3L
Posts: 51
Joined: Fri Sep 29, 2017 7:07 am

Re: 14.31

Postby Matthew Lee 3L » Fri Feb 23, 2018 3:25 am

If the E is positive, this means that deltaG is negative which means the reaction is favorable. When it is favorable, there will be a higher concentration of products, causing K to be greater than 1.

204932558
Posts: 23
Joined: Fri Sep 29, 2017 7:05 am

Re: 14.31

Postby 204932558 » Sat Feb 24, 2018 11:09 pm

If Ecell is positive, G is negative according to G=-nEf. It means the forward reaction is spontaneous and therefore favored, resulting in a K greater than 1.


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