## 14.47

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Essly Mendoza 1J
Posts: 25
Joined: Fri Sep 29, 2017 7:04 am

### 14.47

Hi guys I'm stuck number 47 part A:Calculate the reaction quotient, Q, for the following cell reactions, given the measured values of the cell potential. Balance the chemical equations by using the smallest whole- number coefficients. I don't know where the solutions manual got the values for E cathode ( +1.67 V) and E anode (+0.15V) when the only E value given in the problem was E = +1.33 V. The values for the cathode and anode were found for the half reactions Pb^4+ (aq) +2e- --> Pb^2+ (aq) and Sn^2+ (aq)-->Sn^4+(aq) +2e-.

Lena Nguyen 2H
Posts: 51
Joined: Fri Sep 29, 2017 7:06 am
Been upvoted: 1 time

### Re: 14.47

Both the E values can be found by looking up those half-reactions in Appendix 2B.

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