## 14.37 part a

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Paula Sing 1J
Posts: 36
Joined: Fri Sep 29, 2017 7:06 am

### 14.37 part a

When calculating the cell potential of the cell given in part (a) why are you allowed to omit Cl as is shown in the solutions manual?

Ishan Saha 1L
Posts: 60
Joined: Fri Sep 29, 2017 7:03 am

### Re: 14.37 part a

This is possible because HCl is aqueous, and thus dissolves into H+ and Cl- ions. Since the other reactant/product is H2, the half reaction only involves the H+ ion from HCl.

Alexandria Weinberger
Posts: 51
Joined: Fri Sep 29, 2017 7:03 am

### Re: 14.37 part a

HCl will dissolve into H+ and Cl- ions in solution. In the reaction, Cl- does not react with anything and therefore does not contribute to the balancing of the half reactions.

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