## 14.47

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Glendy Gonzalez 1A
Posts: 52
Joined: Fri Sep 29, 2017 7:07 am

### 14.47

For part a. in the solution manual the value of Q is 10^6, but I keep getting 3269017. What am I doing wrong? Isn't the e^15=3269017.

Lena Nguyen 2H
Posts: 51
Joined: Fri Sep 29, 2017 7:06 am
Been upvoted: 1 time

### Re: 14.47

Your answer is correct, and the solutions manuals just rounds down to 10^6 to have one significant figure.

Naveed Zaman 1C
Posts: 62
Joined: Fri Sep 29, 2017 7:04 am
Been upvoted: 2 times

### Re: 14.47

I think that's the right answer. The book might just have the wrong answer. If you follow all the steps in the solutions manual, you should end up with e15 = 3269017, not 106

Jingyi Li 2C
Posts: 56
Joined: Fri Sep 29, 2017 7:06 am

### Re: 14.47

Yes, the actual number should be 3269017. The answer gives 10^6 because this part is the most significant one.

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