## Q for the concentration cell

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Sophie Krylova 2J
Posts: 59
Joined: Fri Sep 29, 2017 7:06 am

### Q for the concentration cell

In example 14.10 it says that to find Q you need to divide left side by the right side concentration. Why isn’t it the other way around - like products over reactants and hence right over left?

Sarah_Stay_1D
Posts: 57
Joined: Sat Jul 22, 2017 3:00 am
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### Re: Q for the concentration cell

Sophie Krylova 2J wrote:In example 14.10 it says that to find Q you need to divide left side by the right side concentration. Why isn’t it the other way around - like products over reactants and hence right over left?

The left side (anode) is actually the product. In a concentration cell the lower concentration is always the product. Therefore your reaction would be Ion (aq, higher concentration) -----> Ion (aq, lower concentration). So you Q would then be [lower concentration]/[higher concentration].

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