Test 2 Question 8 Part B


Moderators: Chem_Mod, Chem_Admin

Post Reply
Gwen Peng 1L
Posts: 36
Joined: Sat Jul 22, 2017 3:01 am

Test 2 Question 8 Part B

Postby Gwen Peng 1L » Sat Mar 17, 2018 7:18 pm

It says that I- is the anode and Cl- is the cathode and gives the following:
[I-] = 0.025 M
[Cl-] = 0.67 M
Then it asks to calculate Q. Wouldn't you just use Q= [anode]/[cathode]= [0.025]/[0.67] to calculate?
I am asking because this is what I did, but my answer was marked wrong.
Top
904940852
Posts: 53
Joined: Fri Sep 29, 2017 7:07 am

Re: Test 2 Question 8 Part B

Postby 904940852 » Sat Mar 17, 2018 7:26 pm

For this one Q= [H+]^s[HCl]^2/[Pressure of H2]
Top
Gwen Peng 1L
Posts: 36
Joined: Sat Jul 22, 2017 3:01 am

Re: Test 2 Question 8 Part B

Postby Gwen Peng 1L » Sat Mar 17, 2018 8:55 pm

904940852 wrote:For this one Q= [H+]^s[HCl]^2/[Pressure of H2]

Can you please explain why you would use this?
Top
Post Reply

Return to “Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)”

Who is online

Users browsing this forum: No registered users and 2 guests