## 14.13 6th Edition

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Lauryn Shinno 2H
Posts: 59
Joined: Fri Sep 28, 2018 12:24 am

### 14.13 6th Edition

I understand cell diagrams go anode||cathode, but what about the order of the anode ions and cathode ions? I've heard to write it reactants|products and to put it in order depending on the phase with the solids on the outside. However, in 14.13 part b, the cell diagram is Pt(s)|I^-(aq)|I2(s)||Ce^4+(aq),Ce^3+(aq)|Pt(s) with the I2 solid on the inside. And in 14.13 part c, the cell diagram is Pt(s)|H2(g)|H+(aq)||Cl-(aq)|Cl2(g)|Pt(s), with the product on the inside. How does this work?

Eshwar Venkat 1F
Posts: 32
Joined: Fri Sep 28, 2018 12:22 am

### Re: 14.13 6th Edition

Your solid inert conductor, which is Pt (s) in both of these cases, is what is supposed to be written on the outside. You always have to write in the order of reactants|products. In the case of the first example, the I-(aq) is being oxidized to form I2 (s), which is why the reaction is written that way.

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