Nernst equation with K and Q


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Sydney Tay 2B
Posts: 64
Joined: Fri Sep 28, 2018 12:20 am

Nernst equation with K and Q

Postby Sydney Tay 2B » Mon Feb 25, 2019 9:07 pm

Can someone explain what the difference is between the E value that is found when you take the log of K and Q and how can we use that number to determine which way the reaction will proceed?

Miya Lopez 1I
Posts: 62
Joined: Tue Nov 14, 2017 3:00 am
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Re: Nernst equation with K and Q

Postby Miya Lopez 1I » Mon Feb 25, 2019 9:13 pm

When you change the log of Q to the log of K, you know that the reaction has reached equilibrium. I also am not sure how we determine which way the reaction will proceed.

Nada AbouHaiba 1I
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Joined: Fri Sep 28, 2018 12:28 am
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Re: Nernst equation with K and Q

Postby Nada AbouHaiba 1I » Mon Feb 25, 2019 10:05 pm

To see which way the reaction proceeds you would just compare Q and K with one another. If Q is less than K then it will proceed to the right and if Q is greater than K then it will proceed left.


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