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### Nernst equation with K and Q

Posted: **Mon Feb 25, 2019 9:07 pm**

by **Sydney Tay 2B**

Can someone explain what the difference is between the E value that is found when you take the log of K and Q and how can we use that number to determine which way the reaction will proceed?

### Re: Nernst equation with K and Q

Posted: **Mon Feb 25, 2019 9:13 pm**

by **Miya Lopez 1I**

When you change the log of Q to the log of K, you know that the reaction has reached equilibrium. I also am not sure how we determine which way the reaction will proceed.

### Re: Nernst equation with K and Q

Posted: **Mon Feb 25, 2019 10:05 pm**

by **Nada AbouHaiba 1I**

To see which way the reaction proceeds you would just compare Q and K with one another. If Q is less than K then it will proceed to the right and if Q is greater than K then it will proceed left.