6th edition 14.47


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Kim Tran 1J
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Joined: Fri Sep 28, 2018 12:24 am

6th edition 14.47

Postby Kim Tran 1J » Mon Mar 04, 2019 8:10 pm

Calculate the reaction quotient, Q, for the following cell reactions, given the measured values of the cell potential. Balance the chemical equations by using the smallest whole number coefficients:
a) Pt(s) | Sn4+(aq),Sn2+(aq) || Pb4+(aq),Pb2+(aq) | C(gr), E=+1.33 V

The answer I got for this problem was Q = 2.68 x 10^6 (approx. 3.00 x 10^6). The solution manual says Q = 10^6. How much should we round for these types of problems? What are the sig figs? Or is my answer just off?

Christopher Tran 1J
Posts: 77
Joined: Fri Sep 28, 2018 12:15 am

Re: 6th edition 14.47

Postby Christopher Tran 1J » Mon Mar 04, 2019 9:03 pm

I also was unsure about why they rounded to one sig fig. I tried it with the log equation instead of ln, and got 10^6 that way.

Charles Hood Disc 1C
Posts: 39
Joined: Fri Sep 28, 2018 12:19 am

Re: 6th edition 14.47

Postby Charles Hood Disc 1C » Mon Mar 04, 2019 9:41 pm

I got the same answer, it seems as though they chose to round early from 14.7 to 15. However, this would not explain the discrepancy.

Rimsha Hussaini 1A
Posts: 31
Joined: Fri Sep 28, 2018 12:20 am

Re: 6th edition 14.47

Postby Rimsha Hussaini 1A » Tue Mar 05, 2019 1:43 pm

I got 2.68 * 10^6 as well using ln, but why would we get just 10^6 (a completely different answer) by using log instead ln?

Aurbal Popal
Posts: 63
Joined: Fri Sep 28, 2018 12:27 am

Re: 6th edition 14.47

Postby Aurbal Popal » Sat Mar 09, 2019 9:16 pm

Just wanted to say I also got that answer... We have this same exact question in the seventh edition (6.N13) so I am also confused as to why they completely disregarded the 2.68


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