Textbook Problem 6O #1

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Textbook Problem 6O #1

Postby Rami_Z_AbuQubo_2K » Tue Mar 05, 2019 2:16 pm

Why do we have to use 2H2O-->O2 + 4H + 4e- in this problem. Also where do they get the value of 1.23 for Enaught and why is Ni2+ half reaction the cathode and not the anode even though we have typically tried to create the most positive E.

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Re: Textbook Problem 6O #1

Postby aisteles1G » Tue Mar 05, 2019 3:53 pm

I was also really having trouble with this and found this old post: viewtopic.php?t=3354 the explanations in the answers are pretty helpful in understanding the Enaught value!

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