## Concentration cell textbook question 6N. 3A self test [ENDORSED]

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Samantha Chung 4I
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### Concentration cell textbook question 6N. 3A self test

For 6N. 3A self test 7th editon, how do we know what is the product/reactant in Q as the question does not specify if the 1.0M of solution is on the left or right? Im assuming the saturated solution is the product, but why exactly is that the case?

Chem_Mod
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### Re: Concentration cell textbook question 6N. 3A self test  [ENDORSED]

Remember in class I discussed:

R ---> P

[R] concentration is higher in a concentration cell
[P] concentration is lower in a concentration cell

Also,

The Ag+(aq) is forming (increasing) on the left (in the cell diagram) and therefore the product.

The Ag+(aq) is decreasing on the right (in the cell diagram) and therefore the reactant.

Screen Shot 2019-03-08 at 1.18.25 PM.png (84.01 KiB) Viewed 39825 times

jane_ni_2d
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### Re: Concentration cell textbook question 6N. 3A self test

so its correct that the anode is always on the left of the concentration cell right?

Kobe_Wright
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### Re: Concentration cell textbook question 6N. 3A self test

jane_ni_2d wrote:so its correct that the anode is always on the left of the concentration cell right?

Yes.

Philip
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Joined: Sat Sep 07, 2019 12:16 am

### Re: Concentration cell textbook question 6N. 3A self test

So in a concentration cell, is the anode always the one with the lower concentration?

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