CHEMISTRY COMMUNITY

For part c, why is the standard potential of the reaction negative when the half reaction potentials were 0 and +1.36 and neither half reaction had to be flipped?
Additionally, when both pressures and concentrations are given, do you not have to convert the pressure into a concentration? In this question, the solutions manual only changed torr to atm but left it as atm when putting it into the Q equation.

The cell diagram is anode left and cathode right and based on that you can calculate the cell potential (Cathode - anode). If you have both gas and a.q when writing Q, use concentration for a.q and bar for gas.