7th 6.65

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Ray Guo 4C
Posts: 90
Joined: Fri Sep 28, 2018 12:15 am

7th 6.65

Can anyone tell me how to arrive at this answer?
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Chem_Mod
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Re: 7th 6.65

Please attempt the problem, show us your work, so we can gage where you may be struggling with it.

Ray Guo 4C
Posts: 90
Joined: Fri Sep 28, 2018 12:15 am

Re: 7th 6.65

I used $E=-\frac{RT}{NF}lnQ=-\frac{8.314\times 298.15}{1\times 96485}ln\frac{10^{-14}}{10^{-7}}\approx 0.414$. I thought Q is between 10^-7 and 10^7, but the answer seems to imply that instead it should be between 10^-14 and 10^14.

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